What is the absorbance?
Concentration is 8.0 mg/L and Transmittance is 29.6, How do you find the absorbance?
Answer:
Transmittance will be a percentage or %T so to get in absolute unit you first divide %T/100 to To
To = %T/100 = 0.296
A = -log(To)
A = -log(0.296) = 0.53
ref: http://en.wikipedia.org/wiki/transmittan...
Presumably what was used was a spectrophotometer. What this instrument does is shine a light through a solution in a special tube, then measures how much light was absorbed by the solution, and how much was transmitted through the solution to something that measures the light behind the tube. The light can't go anywhere else, so anything not transmitted must have been absorbed. If transmittance is 29.6%, then absorbance was 70.4%.
hopefully this will let you work it out:
the total radiation that is supplied is split into two parts. Part of it is absorbed, and part is transmitted. Total - transmitted = absorbed. use E=hf, c=[lambder]f and [ ] = n/v
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