Balancing Redox Reactions?

Mn ^2+ (g) + Fe3+(aq)  MnO4-(aq) + Fe2+(l)
Balance using the half reactions method.
^= up in the air not below

my answer:
Mn^2+ +Fe^3+ +H2O –––> MnO4^– + Fe^2+ +H^+

if it is wrong help!

Answer:
Mn2+ + 4H2O -> MnO4- + 5e- + 8H+
Fe3+ + e- -> Fe2+

So,

Mn^2+ + 5 Fe^3+ + 4 H2O –––> MnO4^– + 5 Fe^2+ + 8 H^+

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