What mass of sodium, Na, will react completely with1.00 L of chlorine gas, Cl2, at STP?

2 Na(s) + Cl2(g) ---> 2 NaCl(s)

Atomic Molar Mass
Na 23.0 g•mol–1

(A) 0.516 g (B) 1.03 g (C) 2.05 g (D) 46.0 g

Answer:
Answer: "C" Calculations shown below

First, the number of moles of chlorine gas at STP must be determined. Using PV = nRT, solve for n.

n = PV / RT at STP, P = 1.00atm, T = 273.15K, and R = 0.08296 L atm / K mol. The volume given in the problem is 1.00 L.

n = (1.00atm)(1.00L) / (0.08206)(273.15K) = 0.0446 moles Cl2

Determine the grams of sodium that will react with 0.0446 moles Cl2

= 0.0446 mol Cl2 (2 mol Na / 1 mol Cl2) (23.0g Na / 1 mol Na)
= 2.05g Na
C

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