What mass of sodium chloride remains when 250 mL of a 0.200 M solution of sodium chloride is carefully...?

...evaporated to dryness?

Atomic Molar Masses
Cl 35.5 g•mol–1
Na 23.0 g•mol–1

A) 2.93 g (B) 11.7 g (C) 14.6 g (D) 58.5 g

Answer:
Answer: "A" calculations shown below.

To determine the number of moles of NaCl in the solution, multiply the volume(L) times the molarity (M = moles/L).

(0.250L)(0.200M) = 0.0500 moles of NaCl

The mass can be determined using the molar mass of NaCl. mm = 35.5 + 23.0 = 58.5 g/mol

0.0500 moles of NaCl (58.5g NaCl / mol NaCl) = 2.93g NaCl
A) 2.93 g

0.200 mols of NaCl________1000 ml
0.05 mols of NaCl= x_________250 ml

1 mol of NaCl________58.5 g
0.05 mol of NaCl______ x= 2.925g or 2.93 g

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