Which substance is oxidized in this reaction?

3Cu0+ + 8H+ + 2NO3– ---> 3Cu2+ + 2NO + 4H2O



A) NO (B) NO3– (C) H+ (D) Cu0+

Answer:
Well, i hate chemistry, but oxidation describes the loss of electrons.

so which bit loses an electron?

my guess would be NO3– since the NO on the other side is no longer an anion..
HYDROGEN!
Remember LEO and GER. LEO = loss of electrons, oxidisation and GER is gain of electrons, reduction.
Whoever said it was hydrogen was wrong. The hydrogen just helps balance out the redox reaction. Hydrogen always has a charge of positive or negative one.

The substance oxidized here is the CuO+ (D).
Oxygen just about always has a charge of -2, which means the charge of the Cu in the CuO+ is +1, while on the right side of the reaction in the Cu2+ it's +2. The charge on the Cu increased, which means the copper lost an electron, or underwent oxidization.

Hope that helped!

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