What is the molarity of a Na3PO4 solution if adding AgNO3 to 50ml of it produces 2.05g Ag3PO4?

Predict and balance the equation first.

Answer:
Na3PO4 + 3AgNO3 = Ag3PO4 + 3NaNO3
net ionic is
PO4(3-) + 3Ag+ = Ag3PO4

(2.05g Ag3PO4)(1 mol Ag3PO4/ 418.58g Ag3PO4)
=
.00490 moles Ag3PO4

(.00490 moles Ag3PO4)( 1 mol Na3PO4/ 1 mol Ag3PO4)
(Get this from the reaction^^^)
=
.00490 moles Na3PO4

(.00490 moles Na3PO4)/(.050L) = .098M Na3PO4

Hope that helps

The answers post by the user, for information only, FunQA.com does not guarantee the right.



More Questions and Answers:
  • Are L-peptid amino acids found in butter?
  • Carborane Formula?
  • How can we remove the stink on the crustacean shells?
  • What is the use of alcohol lamp in laboratory?
  • Which compound is predominently covalent?
  • In a swimming pool, what makes the water hard?
  • What is the blow-by phenomenon of syringe handling in gas chromatography?
  • I have the molar mass, sample mass and # of moles of a substance.how do i find the #of molecules/formula units
  • What are the most unbelievable chemical reactions of the elements, like alcohol, antimony, tungsten, etc. ??