Calculate the molarities of these ions in the following two solutions:?

[Na+], [Cl-], and [Mg+2] in an aqueous solution that is 0.438M NaCl and 0.0512M MgCl2

Answer:
These are strong electrolytes
NaCl >> Na+ + Cl-
MgCl2 >> Mg2+ + 2Cl-
[ Na+] = 0.438 M
[ Mg2+] = 0.0512 M
[ Cl-] = 0.438 + ( 0.0512 x 2 ) = 0.540 M
Na+ = .438 M
Cl- = .540 M = (.438 + 2(.0512))
Mg2+ = .0512 M

All completely dissociate.

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