Explain the mechanism for hydroboration of methylcyclohexene. Comment on the applicablity of Markovnikov's rule for this reaction.
Please help and explain, I'm confused. Thanks
Answer:
Well hydroboration is typically anti-Markovnikov. So the hydrogen goes to the C1 carbon (bearing the methyl group) and the boron goes to the C2 carbon (bearing the hydrogen) of the double bond. This is because the BH bond is slightly polarized B(+)H(-) and the developing positive charge is more stable on the carbon bearing more substituents. After oxidation, you'll have 2-methyl-cyclohexanol.
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