I Need Help in Chemistry?
What is the binding energy per nucleon in J of Co nucleus The mass of Co is 59.9338amu.
This is what I did so far---
P- 27(1.00728)=27.19656
N-33(1.00867)=33.28611
and the total mass is 60.48267
so I subtract the mass os Co and that gave me .54887
so I took the equation changeE=c^2times the changem
and got 8.21x10^-11
but that is not one of the answers that I need
the following is what I have to choose from:
1. 9.432x10^-13
2.1.368x10^-12
3. 3.039x10^-12
4. 2.487x10^-12
5. 7.009x10^-12
Can someone show me where I am going worng
Thanks
Answer:
The answer is B. It is E/nucleon so you have to divide your ans by (27+33)
I would just flip a coin or throw a dart at it. You would have just as good a chance as if I told you.
I can't really tell you what your doing wrong, seems a bit out of place, as to what your doing. I hated Chemistry, but i do well in that subject, my pick would be answer 1. im 85 percent sure of that.
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This is what I did so far---
P- 27(1.00728)=27.19656
N-33(1.00867)=33.28611
and the total mass is 60.48267
so I subtract the mass os Co and that gave me .54887
so I took the equation changeE=c^2times the changem
and got 8.21x10^-11
but that is not one of the answers that I need
the following is what I have to choose from:
1. 9.432x10^-13
2.1.368x10^-12
3. 3.039x10^-12
4. 2.487x10^-12
5. 7.009x10^-12
Can someone show me where I am going worng
Thanks
Answer:
The answer is B. It is E/nucleon so you have to divide your ans by (27+33)
I would just flip a coin or throw a dart at it. You would have just as good a chance as if I told you.
I can't really tell you what your doing wrong, seems a bit out of place, as to what your doing. I hated Chemistry, but i do well in that subject, my pick would be answer 1. im 85 percent sure of that.
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