Balance the equation:NH3(g) + O2(g) --> N2(g) + H2O(l)?

Then, What is the enthalpy change for the reaction? Include units.

Answer:
2NH3(g) + 1.5O2(g) --> N2(g) + 3H2O(l)

or if you want whole numbers:
4NH3(g) + 3O2(g) --> 2N2(g) + 6H2O(l)

∆H° = -1267.3 kJ/mol
4NH3 + 3O2 -> 2N2 + 6H2O
shouldn' it be 4NH3 + 5O2 ------> 4NO + 6H2O ?

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