325 ml of Helium gas is heated from 25.0 C to 32.3o C. what is the new volume of He?
Answer:
You can use the General Gas Law for this equation:
P1V1/n1T1 = P2V2/n2T2
Since pressure or number of moles isn't changing, you can either disregard or assign a numerical value of "1". This will give you a new equation:
V1/T1 = V2/T2
Since you are looing for a final volume, V2, rearrange to solve for V2
V2 = V1*T2/T1
Now solve for V2
V2 = 325 mL*32.3C/25.0C
V2 = 420 mL (with sig figs)
Hope this helps.
You can use charles law i:e
V/T=v/t
V=325ml, T=25.0C=273+25=298k
v=? t=32.2C=273+32.2=305.5K
now putting d values,
325/298=v/305.5
v=333.175L
hope dis will help u.
note that for charles law temp should b in kelvin(K) and pressure shuld b constant .
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