An alcoholic iodine solution ("tincture" of iodine) is prepared...?

An alcoholic iodine solution ("tincture" of iodine) is prepared by dissolving 5.55 g of iodine crystals in enough alcohol to make a volume of 245 mL. Calculate the molarity of iodine in the solution.

I've put in a million different answers to my web assingment but it won't give it to me.

The molar mass of Iodine is 126.9

Answer:
5.55gI2/245mL x 1molI2/254gI2 x 1000mL/1L = 0.0892M
wanna know how to retrieve them?
empty bottle add same amount of h2o add 2 drops h2so4(sulfric acid) add drops of bleach until it turns really dark watch dark crystals fall to th ebottom
The molar mass of Iodine is 126.9 but iodine is diatomic,I2.

5,55/(126.9x 2) = 5.55/253.8 = 0.0219 moles

0.0219 moles/0.245 liters= 0.0894 molarity

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