Enthalpy, Internal Energy and PV Work?

An electrical heater delivers 2.390 kJ of energy (as heat) to a system consisting of the gas inside a cylinder having a movable piston. As a result, the piston moves against a constant external pressure such that P DV = 0.717 kJ. What is the change in internal energy for the system? Answer to the nearest 0.001 kJ.

Answer:
The piston moves and PΔV is positive. So work is done by the system. There is a loss of enthalpy in the process.

We know that
Δq = ΔU + PΔV
So,
ΔU = Δq - PΔV
ΔU = 2.390-0.717
ΔU = 1.673 kJ

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