Homework help! pls...?
This is a chemistry problem..
explaining is much better than giving the answer,
but giving the answer will also help haha,,
The specific heat of urea is 1.339 J/g degree C. If one adds 60.0J of heat to 10.0 g of urea at 20 degree C. What woyld be the final Temperature?..
thanks a lot!
Answer:
60.0J = (10.0g)(Tf - 20C)(1.339J/g)
from heat = (mass)(Tf - Ti)(sp)
60.0J = 13.39J/g (Tf - 20C)
4.48 = Tf - 20C
Tf = 24.48 or 24.5C
change in temperature(theta)=Q/ms
where s is the specific heat capacity of the substance.
change in temperature=60/(10*1.339)
=60/13.39
=4.481ºC.
therefore final temperature=20ºC+4.481ºC=24.48...
Ok now, all u have to do is take a look at ur measurement units.
the specific heat is in J per mol, per degree C.
meaning, that is the energy (in J) needed to induce a change of 1 degree C in 1 g of substance.
so u have 60J and 10g, meaning the equivalent of 6J pro 1g.
all u have to do now is figure how many times the 1.339J/degree (we already have the equivalent for 1 g, so no need to worry ´bout the grams any more) fit in the 6J that we have. and that will give u the temperature change of ur urea.
Use E = mcQ
Where
E is the energy
m is the mass of urea
c is the specific heat capacity of urea
Q is the change in temperature (the unknown in this case)
So...rearrange:
E = mcQ
Q = E/mc
Substitute:
Q = 60.0/(10.0 x 1.339)
Q = 4.480 degree C
And add on to the inital temperature for the final:
20.0 + 4.48 = 24.5 degrees C
Always make sure that the specific heat capacity units (J/g) match those of mass (g) and energy (J), otherwise you have to convert.
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Chemistry 2 Equilibrium Problem?
explaining is much better than giving the answer,
but giving the answer will also help haha,,
The specific heat of urea is 1.339 J/g degree C. If one adds 60.0J of heat to 10.0 g of urea at 20 degree C. What woyld be the final Temperature?..
thanks a lot!
Answer:
60.0J = (10.0g)(Tf - 20C)(1.339J/g)
from heat = (mass)(Tf - Ti)(sp)
60.0J = 13.39J/g (Tf - 20C)
4.48 = Tf - 20C
Tf = 24.48 or 24.5C
change in temperature(theta)=Q/ms
where s is the specific heat capacity of the substance.
change in temperature=60/(10*1.339)
=60/13.39
=4.481ºC.
therefore final temperature=20ºC+4.481ºC=24.48...
Ok now, all u have to do is take a look at ur measurement units.
the specific heat is in J per mol, per degree C.
meaning, that is the energy (in J) needed to induce a change of 1 degree C in 1 g of substance.
so u have 60J and 10g, meaning the equivalent of 6J pro 1g.
all u have to do now is figure how many times the 1.339J/degree (we already have the equivalent for 1 g, so no need to worry ´bout the grams any more) fit in the 6J that we have. and that will give u the temperature change of ur urea.
Use E = mcQ
Where
E is the energy
m is the mass of urea
c is the specific heat capacity of urea
Q is the change in temperature (the unknown in this case)
So...rearrange:
E = mcQ
Q = E/mc
Substitute:
Q = 60.0/(10.0 x 1.339)
Q = 4.480 degree C
And add on to the inital temperature for the final:
20.0 + 4.48 = 24.5 degrees C
Always make sure that the specific heat capacity units (J/g) match those of mass (g) and energy (J), otherwise you have to convert.
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