Calculate the volume in liters and mL of a .324 Molar solution of H2SO4 required to react completely?
H2SO4+Na2CO3 -------> Na2SO4+CO2+H20
Please if you would explain how you got the answer so that i may better understand how to solve questions like this.
Answer:
The equation tells you that 1 mole of H2SO4 reacts completely with 1 mole of Na2CO3- a 1:1 ratio.
You have 2.792 grams of Na2CO3. How many moles of Na2CO3 do you have? The molecular weight of Na2CO3 is 106. So 2.792 grams / 106 grams/mole = 0.02634 moles of Na2CO3.
Liters x Molarity = moles (because molarity = moles per liter)
0.324 x L = 0.02634 moles
L = 0.02634 / 0.324 = 0.08130 Liters of 0.324 M H2SO4.
(that is 81.30 mL)
Step 1: Number of moles of Na2CO3
Molar mass of Na2CO3 = (23*2) + 12 + (16*3) = 106 gmol-1
Thus:
106g Na2CO3 are equivalent to 1 mol
2.792 g are equivalent to ? ===> 2.792 * 1 /106 = 0.02634 mol
Step 2: Stoichiometry
From the equation:
1 mol of Na2CO3 reacts with 1 mol of H2SO4
Thus 0.02634 mol Na2CO3 react with 0.02634 mol H2SO4
Step 3: Volume of H2SO4
0.324 moles are found in 1000mL of solution
0.02634 mol are found in ? mL ==> 0.02634 * 1000 / 0.324 = 81.3 mL = 0.0813 L
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