What volume of the 10.0 M NaOH solution do you use?
you need to prepare 600. mL of 2.00 M NaOH solution from a 10.0 M NaOH solution
Answer:
M1V1 = M2V2
M1 = 10 M
V1 = ?
M2 = 2M
V2 = 600 ml
V1 = M2V2 / M1
V1 = (2)(600) / 10
V1 = 120 ml
Number of moles of solute in diluted solution:
In 1000 mL there are 2.00 mol NaOH
In 600 mL there are ? ==> 600 * 2 /1000 = 1.2 mol NaOH
Since dilution process involves addition of solvent only, all the moles of NaOH must come from the 10M solution.
Thus:
10 moles of NaOH are present in 1000mL solution
1.2 mol NaOH are present in ? ===> 1.2 * 1000 / 10 = 120 mL (Answer)
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Answer:
M1V1 = M2V2
M1 = 10 M
V1 = ?
M2 = 2M
V2 = 600 ml
V1 = M2V2 / M1
V1 = (2)(600) / 10
V1 = 120 ml
Number of moles of solute in diluted solution:
In 1000 mL there are 2.00 mol NaOH
In 600 mL there are ? ==> 600 * 2 /1000 = 1.2 mol NaOH
Since dilution process involves addition of solvent only, all the moles of NaOH must come from the 10M solution.
Thus:
10 moles of NaOH are present in 1000mL solution
1.2 mol NaOH are present in ? ===> 1.2 * 1000 / 10 = 120 mL (Answer)
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