Five beans have a mass of 2.1g. How manu beans are in 0.454kg of beans?
Answer:
1081 beans is the best answer that could be determined from the information that you supplied.
This was correctly calculated in the answers above, first by finding the average mass of the 5 measured beans and dividing this into the total mass of beans (454 grams).
A better solution to the problem would have been to measure the mass of 10 to 20 beans and calculate not only the average (mean) mass, but also the standard deviation of the measurements. This would have resulted in calculating a range of numbers (perhaps 1071 to 1091) beans with a reliability of 95% or better.
one bean have a mass of 2.1/5 gram convert into kg then it will be mass of 1 bean and now divide in this way
0.454/(2.1/5)
the decimal figure will tell u that when there is a weight of 0.454kg possesed by beans than there r [0.454/(2.1/5)] beans pressent in it
5 x = 2.1
=> x = (2.1/5) ... this is the weight of each bean
now let "n" beans weigh 0.454 kg = 454 g
so n* (2.1/5) = 454
=> n = 454*5/2.1 = 1080.95 ≈ 1081 beans
Jeez, i found the # are 1080.95 beans!!
0.454 kg is 454 g of beans. Thus since 5 beans have a mass of 2.1 g...
set of 5 beans = 454g/2.1g=216 sets
216 set x 5 beans= 1080 beans all together
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