Longer chem question please help?

A saturated solution of strontium hydroxide is prepared and the excess solid strontium hydroxide is allowed to settle. A 25mL aliquot of the saturated solution is withdrawn and transferred to an Erlenmeyer flask and two drops of methyl orange indicator are added A .073 M HCl solution (titrant) is dispensed from a buret into the solution (analyte) The solution turns from yellow to a very faint red after the addition of 29.5mL
A)How many moles of hydroxide ion are neutralized in the analysis
B)What is the molar concentration of the hydroxide ion in the saturated solution
C)What is the molar solubility of strontium hydroxide
D)What is the solubility product Ksp for strontium hydroxide
E)For the determination of the Ksp for strontium hydroxide, the stroichiometric point (as determined by the endpoint of methyl orange indicator) should not be surpassed.Suppose the stoichiometric point is an experiment is surpassed. Will the reported solubility product be too high,low or unaffected why

Answer:
Moles HCl = 29.5 x 0.073 / 1000 = 0.00215
2 HCl + Mg(OH)2 >> MgCl2 + 2 H2O
the ratio between HCl and Mg(OH)2 is 2 : 1
A) Moles Mg(OH)2 = 0.00215 / 2 = 0.00108
B) Moles OH- = moles H+ = 0.00215
V = 25 mL = 0.025 L
[OH-] = 0.00215 / 0.025 = 0.0860 M
C) Concentration of dissolved Mg(OH)2 = 0.00108 / 0.025 = 0.0432 M. This gives the moles of Mg(OH)2 that can dissolve per liter.
D) Ksp = [Mg2+] [OH-]^2

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