What is the full balanced equation to the following chemistry reaction?

Propene + Bromine [water] = ??

C(3)H(6) + Br(2) = ??

thanks

Answer:
C3H6 + Br2 => C3H6Br2

or

CH2=CH-CH3 + Br2 => CH2Br-CHBr-CH3

The bromines simply are added to the carbons where the double bonds were located. The product is 1,2-dibromopropane.
C3H6 + Br2 = C3H6Br2

Dibromopropane - the bromine will add to the propene across the double bond
C3H6 + Br2 -> C3H6Br2

1,2 - Di Bromo Propane.
gives CH2Br-CHBr-CH3 i think

balances itself
it's bromination.
C3H6+Br2=C3H6Br2.(dicolouri... occurs showing that it's an unsaturated hydrocarbon)
C3H6 + Br2 = C3H6Br2 [1,3-dibromopropane or trimethylene dibromide if you want the mouthful version!!]
By bromine water, do you mean Br2 dissolved in water, or HBr? The latter is hydrogen bromide, but the reactions are similar:

propene + bromine = 1,2-dibromopropane

propene + hydrogen bromide = 1-bromopropane *and* 2-bromopropane

For the reaction with hydrogen bromide, you will get more 2-bromopropane than 1-bromopropane.

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