I am stuck on balancing an equation. Can anyone help please?
the reaction of a primary halogenoalkane with aqueous sodium hydroxide
reduction of a nitro compound to a primary amine
any help will be much appreciated I have managed the rest but these 2 have got me stuck.
Answer:
CH3CH2Cl + NaOH (aq) > CH3CH2OH + NaCl
CH3CH2NO2 + LiAlH4 (or any reducing agent) > CH3CH2NH2
These two are balanced, but in general don't bother balancing organic equations, it's not necessary. What's important is understanding the mechanism and the products in different conditions. Don't worry, nobody'll cut marks!! ;)
CH3X + NaOH --> NaX + CH3OH
RNO2 + 3H2 --> RNH2 + 2 H2O
R-CH2-X + NaOH -----> R - CH2 - OH + NaX
R-NO2 + 6[H] -----------> R-NH2 + 2H2O
primary halogenoalkane with aqueous sodium hydroxide...
halogenoalkane + NaOH (aq) --> alcohol + Sodium halide (The reaction must be refluxed)
eg:
bromoethane + NaOH(aq) ---(reflux)---> ethanol + NaBr(aq)
reduction of a nitro compound to primary amines
nitrocompound + [H] ---(Na in ethanol)---> hydroxy amines
eg: (general formula)
rR1C(OH)(CN) + [H]---(Na in ethanol)-> rR1C(OH)(CH2NH2)
note:
r and R1 are variable regions
all you have to do is look at the small numbers in the symbol equasion on the side where the end products are and take them and count up the particles with the particles on the reactents side and then see if you need to add more compounds to equal it. Its kinda hard to explain over the internet. Look in a text book or ask your teacher to help you.
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