Find molar volume of an ideal gas?

At 126 K and 21 atm, compute the molar volume of oxygen gas assuming it is an ideal gas.

Answer:
pV = nRT
molar volume n=1

so V= RT/P R=8.31 T=126 21 atm =21*101325=2127825

V= 8.31*126/2127825=4.92*10^-4m^3... 0.492L
molar volume at STP = 22.4 liters.

22.4 x (126/273.15) x (1/21) = .492 liter = 492 ml
PV = nRT will work for your problem, you can ignore the virial coefficients, since this is an ideal gas.

V = nRT/P
n = 1
R = 0.0821 L.Atm/mol.K
T = 126 K

everything cancels except the liters unit

I get 0.493 L at 126 K and 21 atm

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