A gas at 1250C and 15 atm has a molar volume 9% smaller than that calculated from the perfect gas law. Find the molar volume of the gas.
Answer:
Acc to perfact gas law---- PV = nRT
so.. V= nRT/P
here n=1, R= 0.0821L atmK-, T= 1250+273= 1523k
V = 1*0.0821*1523/15
V= 8.335 L
From question molar vol is 9% smaller than the calculated,then
V= 8.335-9*8.335/100
V=8.335- 0.750 =7.585 L (answer)
pV = nRT
V = nRT / p
when n =1
V = RT /p
T = 1250 + 273 =1523
V = 0.0821 x 1523 / 15 = 8.33 L
8.33 - 9% = 7.58 L
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