Calculate the solubility of dinitrogen in blood that is in contact with air (78% N2) at 4.00 atm, the pressure
Answer:
S= 3.8*10^-4*0.78 =3*10^-4L
you must use 0.78 since at 1 atmosphere , partial pressure is only 0.78 atm and not 1
Data required.
3.84 x 10^-4/1atm = S2/4.00atm
based on the data you have given me, this would be the derived equation. Just solve for S2. I used 1atm because that is the standard pressure of our bodies. :)
The answers post by the user, for information only, FunQA.com does not guarantee the right.
More Questions and Answers: