Reaction Rates Helppp?

If HCl and Na2S2O3 are kept constant, by how many degrees would this reaction have to be heated (from 25 C) to precisely double the reaction rate?.. from a slope of -0.0002 i got an activation energy of 0.016628 J ..so how do i figure this out?

Answer:
Are you sure about the value and unit of your activation energy? Isn't it in kJ/mol?


Anyway, here's the equation:
k2/k1 = exp [- Ea/R ( 1/T2 - 1/T1)]
ln k2/k1 = [- Ea/R ( 1/T2 - 1/T1)]

k2/k1 = 2
R= universal gas constant, 8.31434 J mol-1 K-1
T1=298 K
T2 =? (in Kelvin)

A rule of thumb is that reaction rate doubles for every 10 deg C rise in temperature. Though not applicable to all, your T may be somewhat close to 35 degC (308 K). Just a guess, but check your Ea first before computing. I'm getting a negative value with your Ea.

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