Consider the reaction: 2HgCl2 + C2O4^-2 ---> 2Cl^-1 + 2CO2 + Hg2Cl2 This is a hard one !?

The initial rate of this reaction was determined for several concentrations of HgCl2 and C2O4^-2 and the following rate data was optained:

1; (HgCl2)(M) 0.105; (C2O4^-2)(M)0.15; Rate(M/s) 1.8x10^-5
2; (HgCl2)(M) 0.105; (C2O4^-2)(M)0.30; Rate(M/s) 7.1x10^-5
3; (HgCl2)(M) 0.052; (C2O4^-2)(M)0.30; Rate(M/s) 3.5x10^-5
4; (HgCl2)(M) 0.052; (C2O4^-2)(M)0.15; Rate(M/s) 8.0x10^-6
5; (HgCl2)(M) 0.080; (C2O4^-2)(M)0.10; Rate(M/s) ?

a) what is the rate law for this reaction ?


b) what is the numerical value for the rate constant?



c) What would be the rate for the last set of data ?


Any help or comments would be appricaiated: thx

Answer:
a) rate = k [HgCl2] [C2O4]^2

b) 1.8x10^-5 = k * 0.105 * (0.15)^2
k = 7.6x10^-3

c) rate = 7.6x10^-3 * 0.080 * (0.10)^2
rate = 6.1x10^-6
wow that is hard
i give you a gold star for even thinking of it

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