What is the activation energy of the reaction?

The rate constant of a chemical reaction increased from 0.100s-1 to 3.30s-1 upon raising the temperature from 25.0C to 37.0C.

A)Calculate the value of (1/T2 - 1/T1).
B)Calculate the value of ln (k2/k1).
C)What is the activation energy of the reaction?

Answer:
a) (1/310.15K) - (1/298.15K) = -0.00013K-1
b) ln (3.30s-1/0.100s-1) = 3.496s-1
c) Ea = (-8.3145 J/mol-K)*(3.496s-1 / -0.00013K-1)
Ea = 224 kJ/mol-s

The answers post by the user, for information only, FunQA.com does not guarantee the right.



More Questions and Answers:
  • Cosidering the equation below---when 2.5mol of Mg3N2 are allowed to react, how many mols of H2O also react?
  • What happens if too much phenolphthalein is added to a solution in a titration?
  • Compare the Ka of acids?
  • Why normal saline PH is acidic(5.5)?
  • 50 g of sugar (C12H22O11)is dissolved in 500g water at standard pressure. How much is the boiling point raised
  • How components will seperate in hplc column & what do you mean by polarity?
  • To produce heat energy would we use electricity?
  • Can u plz give me at least 5 biological inventions? plzz.. tnx?
  • Thermodynamics: ice melting question?