What 1/2 reaction would be reduced by Cr(NO3)3 being reduced by 3 electrons?



Answer:
Cr (3+) + 3e- --> Cr (0)

lose electrons oxidation (LEO)
gain electrons reduction (GER)

the chromium is gaining electrons and thus being reduced.
Cr(3+) + 3e- --> Cr
reduction = gaining electrons

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