How much heat is released when 8.5 g of CS2 abd 8.4 of Cl2 are mixed and react according to the following...?

CS2(g)+3Cl2(g)-->S2Cl2(g)CCl4(... delta H=-230 KJ/mol

Answer:
Molar mass of CS2 = 12+64 = 76 g

8.5/76 = 0.112

8.4/71 = 0.118

Cl2 is the limiting reagent.

Thus, heat = 0.118*(-230)/3 = 9.05 kJ
i agree ^ ^ ^ ^ ^ ^ : )

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