Qualitative chemistry problem?
please teach me how to answer this. please also kindly explain the solution if you will answer this question. thanks a lot.
Answer:
NaHCO3 + H2SO4 >> H2CO3 + NaHSO4
molar mass NaHCO3 = 84 g/mol
94.8 : 100 = x : 0.3
x = 0.284 mass of pure NaHCO3
0.284 / 84 = 0.00338 moles NaHCO3
the ratio between NaHCO3 and H2SO4 is 1 : 1 so we need 0.00338 moles H2SO4
Molarity H2SO4 = 0.925 x 2 = 1.85 M
V = moles / M = 0.00338 / 1.85 = 0.00183 L = 1.83 mL
Also, end point is the point where the indicator changes color, so your answer depends on what indicator you use, but regardless of that your answer will be very close to the answer above unless you're using an indicator that changes at a pH of 12 or 2 or something ridiculous.
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