The solubility of lead chloride PbCl2 is 1.6x10^-2M. What is the Ksp of PbCl2?

I have no clue can someone show me how to sit this up please!

Thanks

Answer:
PbCl2(s) <---> Pb²+(aq) + 2Cl-(aq)
- - s - - - - - - - - - -s - - - - - - - 2s

Since the [PbCl2] is 1.6 x10^-2M, then the ratio of the above equilibrium is 1:1:2 (Since there are 2 chlorides)

So, Ksp= [Pb²+][Cl-]²

Ksp= [1.6 x10^-2][3.2 x10^-2]²

Ksp= 1.6 x10^-5

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