Equilibrium Problem - Help PLEASE!!?

For the following reaction Kp = 6.5 x 10^-4 at 308 K:

2NO (g) + Cl2 (g) --> 2NOCl (g)

At equilibrium, Pressure(NO) = 0.35 atm and Pressure(Cl2) = 0.10 atm. What is the equilibrium partial pressure of NOCl (g)?

Answer:
Kp = p(NOCl)^2 / [p(NO)^2 * p(Cl2)]

Solving for p(NOCl) and putting in values, we have

p(NOCl) = [6.E-04 * (0.1) * (0.35)^2]^0.5

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