Balance the following reaction, calculate E^0 cell and state whether the reaction is spontaneous:
Mn^2+ (aq) + Br2 (liq) --> MnO4^- (aq) + Br^- (aq)
Help on this one??
Thanks!
Answer:
4 H2O + Mn(2+) = MnO4(-) + 8 H(+) + 5 e(-)
Br2 + 2 e(-) = 2 Br(-)
Multiply top equation through by 2
Multiply bottom equation through by 5
Add up.
Look up the reduction potential for MnO4(-) going to Mn(2+). Change it's sign.
Look up the reduction potential for Br2 going to Br(-). Leave its sign alone.
Add the two numbers together. If the sum is positive, the reaction is spontaneous.
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