What volume will each of the following occupy at STP?

a] 1.00 mol NO2
b] 18.32 g NO2
c] 6.25E+24 molecules of NO2

-appreciate for your help!

Answer:
1 mol occupies 22.4 L at STP
18.32 g of NO2 x 1 mol / 46 g = 0.398 mol
0.398 mol x 22.4 L / mol = 8.9 L
6.25E+24 / 6.02E+23 = 10.4 mol
10.4 mol x 22.4 L / mol = 233 L

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