What mass of each solute is present in 25g of a solution that contains 5.1% by mass of pottasium nitrate...
Answer:
Just a simple multiplication exercise here...
5.1% of 25g = 25 * .051 = 1.275 g KNO3
7.2% of 25g = 25 * .072 = 1.8 g Na2CO3
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