Molar Concentration: Gas Laws?

A sample of chlorine gas is confined in a 5.0 L container at 228 torr and 27degress Celsius. How many moles of gas are present in the sample?

Help please. I think I have the right answer but I am not sure.
Thanks!

Answer:
PV = nRT

n = PV / RT

P = 228 torr x 1 atm / 760 torr
V = 5.0 L
T = 27 + 273.15 (K)
R = 0.0821 L atm / mol / K

plug and chug

Standard temperature is 0 Celsius
Standard pressure is 760 torr
Standard volume is 22.4 liters.

Multiply 5/22.4 times 228/760 times 300/273 and you get 0.74 moles of Chlorine.

use the equation -

PV = nRT

Ideal Gas Law

from memory, covert Pressure from torr to atm units and temp from celsius to kelvin and use ideal gas constant
R = 0.0821 L atm K-1 mol-1

Should be simple to complete the answer from there.

Cheers :)

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Molar Concentration: Gas Laws?

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