An HCl solution has a pH of 3.10, what is the [OH-] in this solution?
1.3 ´ 10-11M
7.9 ´ 10-4 M
1.3 ´ 103 M
Answer:
1.3 x 10^-11M
One way to answer this questions is to use the fact that
pH + pOH = 14 therefore,
pOH = 14 - pH = 14- 3.10 = 10.9
Just like pH = -log[H+], pOH = -log[OH-],
so pOH = -log[OH-]
10.9 = -log [OH-]
antilog(-10.9) = [OH-] or
[OH-] = antilog (-10.9) = 10^(-10.9) = 1.3 x 10-11 M
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