Chemistry help?

The concentration of iodide ions in a 0.193 M solution of barium iodide is __________.

Answer:
0.306 M

BaI2 >> Ba2+ + 2 I-
[Ba2+] = 0.193 M
[I-] = 2 x 0.193 = 0.306 M
molarity is the same as concentration, just put in a different way.
The unit for molarity is M, and the units for concentration are mol/L. So you have 0.193 mol/L.
barium iodide is made of 1 atom of barium and 1 atom of iodide. the concentration of iodide ions is therefore equal to the number of molecules of barium iodide in the solution, being 0.193M
BaI2 --> Ba2+ + 2I-


BaI2 = 0.193M
I = 2. 0.193 = 0.386M
For every one mole of Barium, there are two moles of Iodine present, therefore concentration of iodine= 0.386M

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