Chemistry compound search.?
-SrCl2
-LiNo3
-Na2CrO4
-Nh4OH
-NiCl2
-Sr(NO3)2
-KrCr2O7
Answer:
hmmm.. Ok, lets eliminate some of the more obvious ones first.
1) NH4OH - liquid - smells like ammonia
2) KCr2O7 - deep red-orange solid - can't miss it
3) Na2CrO4 - bright yellow solid
4) NiCl2 - yellow-green solid (more green than yellow)
That leaves:
SrCl2
Li(NO3)2
Sr(NO3)2
a) dissolve a small amount of sample in water
b) add a few drops of dil. H2SO4
c) if you get a ppt:
you DON'T HAVE Li(NO3)2
d) if you DO get a ppt:
1) dissolve a small amount of sample in water
2) add a few drop of AgNO3 solution
if you get a ppt ==> you have SrCl2
if you DO NOT get a ppt you have Sr(NO3)2
First there is not a single test that differentiate between all of these compounds. Lets break them into groups.
NH4OH can be tested with litmus==turns red to blue (hold red litmus over the compound while GENTLY heating it.
NiCl2 is a green salt and makes a green solution.
Na2CrO4 and K2Cr2O7 (orange) are both yellow but Na salts give a fluffy yellow flame test while K salts give a lavender one.
SrCl2 - LiNO3 and Sr(NO3)2 remain
Only SrCl2 will give a precipitate with AgNO3
Leaving just LiNO3 and Sr(NO3)2
Of these 2 only Sr(NO3)2 will give a precipitate with dilute sulfuric acid.
the last one remaining would be LiNO3 (verified by a red flame test)... Caution... Both Li and Sr salts will give a red flame test so in this case the test is not confirmatory.
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