As the [H+] in a water solution increases the [OH-] decreases?
Answer:
Can you elaborate a little on the question please?
I think you're talking about why [OH-] decreases when an acid is added to water?
It is due to Le Chatelier's Principle. When an acid is added to water, the dissociation of H2O shifts to the left, using up [OH-] and [H+] to produce water. With an excess of H+ this will result in a reduction in [OH-] ions in the solution.
H2O --> H+ + OH-
This is a reversible reaction, I just can't do the equilibrium arrow on here, sorry.
Le Chatelier's Principle states a dynamic equilibrium will act to 'balance out' an excess or deficiency in one of the species in the equation. So an excess of H+ will drive the reaction in the reverse direction, removing [OH-] in the process.
If you're not adding anything to the water, I'm not sure what you're getting at so need more information :o)
True. The [H+] ions are acidic, which means the water solution is becoming more acidic. The base, which would be the [OH-] ions, would then decrease.
your question has no sense...
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