In an aqueous solution the [H+] is 1.0 x 10^-5 M. What is the [OH-]?

1.0 x 10^-9 M
1.0 x 10^-7 M
1.0 x 10^-5 M
1.0 x 10^9 M

Answer:
1.0 x 10^-9; you take the negative log of [H+] to get the pH. Subtract the pH from 14 to calculate the pOH. Take the 10^-pOH to get the concentration of [OH-] in solution.
Another way to answer is
[H+] *[OH-] = 10^-14 M
plug in the no. and you can get the answer.
divide10^-14 by concentration of [H+] and u get (a) part as ur ans.

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