How many moles of H3O+ must be added to 349 mL of a solution to adjust the pH from 7.40 to 5.33? Use E notatio
Answer:
pH = 7.40 >>[H+] = 10^-7.40 = 4.0 x 10^-8 M
moles H+ = 349 x 4.0 x 10^-8 /1000 = 1.4 x 10^-8
pH = 5.33 >> [H+] = 10^-5.33 = 4.7 x 10^-6 M
moles H+ = 349 x 4.7 x 10^-6 /1000 = 1.64 x 10^-6
1.64 x 10^-6 - 1.4 x 10^-8 = 1.63 x 10^-6 ( moles H+ that we have to add )
10^-5.33-10^-7.4
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