Nuclear decay?
235/92 U + 1/0n --> ___ + 135/54 Xe + 2x1/0n
the question is what to put in the blank. The answer is 99/38 Sr but I don't see how you get it.
I couldn't write the numbers vertically..so 235 is the mass, 92 is the number of protons.
Answer:
In uranium nuclei 92 protons and 143 neutrons are there ,on bombardment with the neutron nuclear fission takes place and 2 neutrons are released. As neutrons are charge less particles there is no loss of protons in this process. Hence, on right hand side 92 protons should remain as total.
Therefore, the total of protons in Xe and the Blank space atom should be 92. Now Xe has got 54 protons , so the Blank space atom would be Sr with 38 protons as 54+38 =92
Therefore, Sr with atomic number 38 is the correct option.
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