a solution of 5.0 g benzoic acid (C6H5COOH) in 100.0 g of CCl4 has a boiling point of 77.5 celcius. the boiling point of pure CCl4 is 76.5 Celcius. calculate the molar mass of benzoic acid in the solution based on the boiling point elvention. (Kb for CCl4 is 5.03 celcius/m)
Answer:
delta T = kf m
77.5 - 76.5 = 1 °C
100 g = 0.1 Kg
1 = 5.03 m
m = 1 / 5.03 = 0.199
m = moles / Kg
0.199 = moles / 0.1 Kg
moles = 0.0199 = mass / molar mass
0.0199 = 5.0 / molar mass
molar mass = 5.0 / 0.0199 = 251 g/mol
NOTE this is not the molar mass of benzoic acid but the work is correct
Molar mass of 122.12 g/mol.
The structural formula of benzoic acid is shown. The benzoic acid-ethanol solution at different times.
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