What is the weight of the KCl residue when 3.00 grams of KClO3(s) is decomposed according to the reaction...?

...2KClO3(s) ® 2KCl(s) + 3O2(g)?

a) 0.193 g
b) 1.37 g
c) 1.83 g
d) 2.74 g

Answer:
3.00g KClO3 * (1mol / 122.55g) = 0.02448 mol KClO3
2 mol KClO3 --> 2 mol KCl
so 0.02448 mol KCl
(.02448 mol KCl) * (74.55 g/mol) = 1.82g KCl
c--- 1.83 g is the best answer (1.82 is probably slightly off because of rounding)

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