Can you calculate each of the following quantities in 2.00 mol H3PO4?
Moles of H
Moles of O
Atoms of P
Atoms of O
Answer:
We have 2.00 moles of P ; 1 moles corresponds to 6.02 x 10^23 .
2.00 x 6.02x 10^23 = 1.204 x 10^24 atoms of P
We have 2.00 x 3 = 6.00 moles of H
6.00 x 6.02 x10^23 = 3.61 x 10^24 atoms of H
We have 2.00 x 4 = 8.00 moles of O
8.00 x 6.02 x 10^23 = 4.82 x 10^24 atoms of O
moles of H:
3×2 mol
Moles of O:
4×2mol
Atoms of P
n(P)×Na = 1×2 mol ×6,02×10^23 = 12,04×10^23 atoms
Atoms of O:
4 × 2 mol × 6,02×10^23 = 48,16×10^23 atoms
to answer your original question, no, i cannot calculate each of the quantities in 2.00 mol h3po4.
tell your teacher that, he/she must accept it as it is a real answer to your question.
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