What is the new volume of the gas in liters when the following changes occur in the quantity of the gas...?
A sample containing 1.50 mol neon gas has a volume of 8.00L
Can you please show me step by step on how to get these answers?
A leak allows one-half of the neon atoms to escape
A sample of 25.0 g neon is added to the neon gas already in the container
A sample of 3.50 mol O2 is added to the neon gas already in the container
Answer:
Apply ideal gas law
p·V = N·R·T
(p pressure, V Volume; N number of moles, R universal gas constant, T absolute thermodynamic temperature)
Therefore
V/N = R·T/ p = constant for T and p constant
By changing the number of moles to N' the volume changes to V' :
V'/N' = V/N
<=>
V' = V·(N'/N)
(i)
N drops to N' = N/2
V' = 8L·(1/2) = 4L
(ii)
adding 25g neon raises the number of moles to
N' = 1.5mol + 25g / 20.18g/mol = 2.74mol
=>
V' = 8L · (2.74mol / 1.5mol) = 14.61L
(iii)
adding 35g oxygen raises the number of moles to
N' = 1.5mol + 25g / 32g/mol = 2.59mol
=>
V' = 8L · (2.59mol / 1.5mol) = 13.8L
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