Theoretical yield?
Answer:
3.5 / 6.94g/mol Li = 0.50 mol
3.5 / 28.02g/mol N2 = 0.125 mol --> 0.25mol N
reaction formula is:
6Li + N2 --> 2(Li3N)
ratio of litjhium to nitrogen in product is 3:1
0.5/(3)= 0.13333moles. so Li is limiting reagent and 0.133mole of product will be produced
0.133 * (34.83g/mol Li3N) =4.35g produced theoretically
Ans : 5.83 gram
molecular weight of lithium = 7
molecular weight of nitrogen = 28
the reaction formula is following
6Li + N2 = 2Li3N
so 42 gram of lithium needs 28 gram of nitrogen to produce 70 gram lithium nitride.
dividing all the the number by 12 we get
3.5 gram of lithium needs 2.33 gram of nitrogen to produce 5.83 gram of lithium nitride. the rest of nitrogen will be unused.
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