What volume will 0.431 g of krypton gas occupy at STP?
Answer:
You have to find the moles of Kr (grams/ molar mass) and you get 0.00514 mol. Since the volume of a gas at STP is 22.4 L per mol, the volume is 0.115 L
any one mole of a gas will occupy 22.4 liters at STP.
first, find out how many moles of krypton is .431 g by using a periodic table and dimensional analysis:
.431g Kr | 1 mole Kr .431mole Kr
-------------|---------------- = ------------------- = .005 mole Kr
1 | 83.8 g Kr 83.8 Kr
then, use dimensional analysis again, this time using the 22.4 liters thing:
.005 mol Kr | 22.4 L Kr
------------------------------... = .115 L
1 | 1 mol Kr
Therefore, .0431 g of Kr will occupy .115 L at STP.
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