If 41.38 mL of a sulfuric acid solution reacts with 0.2888g of..?

If 41.38 mL of a sulfuric acid solution reacts with 0.2888g of sodium carbonate dissolved in sufficient water, the molarity of the sulfuric acid solution is

A) 0.658
B) 0.329
C) 0.0658
D) 0.0329
E) 0.987

Answer:
the answer should be C). first, we write the equation i.e.
H2SO4+Na2CO3 --->Na2SO4+H2CO3
from the equation, 1 mole of sulphuric acid react with 1 mole of sodium carbonate. number of moles of sodium carbonate is 0.2888/(22.99x2+12.01+16x3) i.e. 0.0027248. that's mean number of moles of sulphuric acid is the same. from the equation, no. of moles=MV/1000.therefore,M=(0.0...

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