A solute which has i=5, is placed in 5430g of nitrobenzene. if the freezing point is lowered to 3.29 degrees..
Answer:
delta T = kf x i x m
kf of nitrobenzene = 8.10
3.29 = 8.10 x 5 x m
m = 0.0812
molality = moles solute / Kg solvent
moles solute = molality x Kg solvent = 0.0812 x 5.43 Kg = 0.441
0.441 moles weights 37.8 g
37.8 / 0.441 = 85.7 g/mol ( molecular weight )
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